Masters Examination in Mathematics

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Solution. Since (ab)(abc) = (bc) and (abc)(ab) = (ac), it is easy to see that the center of S3 is the trivial subgroup. Therefore, the group of inner automorphisms of S3 is isomorphic to S3 and has size 6. On the other hand, S3 has 3 transpositions. These must be permuted by an automorphism of S3, and a nontrivial automorphism induces a nontrivial permutation. This gives an injective homomorphism from Aut(S3) to S3, which shows that the group of automorphisms of S3 has size at most 6. It follows that Aut(S3) ∼= Inn(S3) ∼= S3.

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تاریخ انتشار 2013